Saponification value calculator explained
Saponification value (SV) expresses how many milligrams of KOH are required to saponify 1 gram of fat or oil. It is determined by refluxing a known mass with excess alcoholic KOH, titrating the unused base with HCl, and comparing the blank and sample titers. This calculator applies
where and are the HCl volumes for blank and sample {blank}, {sample}, is the HCl molarity {molarity}, and is the sample mass {weight}. The result {saponificationvalue} is reported in mg KOH per gram.
Use it to monitor oil quality for soap making, detect adulteration in edible oils, or document QC data for cosmetic bases.
How the conversion works
Each milliliter of 1 N HCl corresponds to 56.1 mg of KOH (the molar mass of KOH). Subtracting the sample titer from the blank reveals how much KOH reacted with the fat. Dividing by the sample mass normalizes the result:
Units and conversions
| Parameter | Units | Notes |
|---|---|---|
| , | mL HCl | Burette readings for blank and sample titrations. |
| mol/L | Normality of the HCl titrant (often 0.5 N). | |
| g | Mass of oil or fat used. | |
| SV | mg KOH per g | Output comparing to literature ranges. |
Worked examples
- Palm oil QC
, , , .
This matches typical palm oil SV values (196-205); the slightly higher value may indicate shorter-chain components.
- Coconut oil lot
, , , .
Coconut oil usually has SV 248-265, so this value suggests the product may be adulterated with longer-chain fats.
Tips and pitfalls
- Keep titrant standardization up to date; SV accuracy depends on .
- Ensure the sample dissolves completely in alcoholic KOH before refluxing.
- Always run blanks alongside samples; atmospheric CO consumption changes over time.
- Compare SV with iodine value or fatty acid profile to pinpoint adulterants.